GCSE Percentages

Step-by-step worked examples and graded practice questions on percentages — finding a percentage of an amount, percentage increase and decrease, reverse percentages and compound interest.

📚 Foundation & Higher ✅ 15 Practice Questions 🔍 Full Worked Examples ⚠️ Common Mistakes

What is a percentage?

"Per cent" means "out of 100" — a percentage is a fraction with a denominator of 100. To use a percentage in a calculation, it's usually easiest to convert it to a decimal first by dividing by 100 (see the Decimals page): 15% = 0.15, and 8% = 0.08.

Finding a percentage of an amount

Worked Example 1
Find 15% of £240.
1
Convert 15% to a decimal: 15% = 0.15
2
Multiply: 0.15 × 240 = 36
Answer£36
15% the whole = £240 £36

The shaded 15% strip represents £36 out of the whole £240 bar.

Percentage increase and decrease

The quickest method is a multiplier: to increase by a percentage, add it to 100% first; to decrease, subtract it from 100%. Then convert to a decimal and multiply.

Worked Example 2
(a) Increase £80 by 20%. (b) Decrease £150 by 30%.
1
(a) 100% + 20% = 120% = multiplier 1.2. Then 80 × 1.2 = £96
2
(b) 100% − 30% = 70% = multiplier 0.7. Then 150 × 0.7 = £105
Answer(a) £96 (b) £105

Reverse percentages

A reverse percentage question gives you the amount after a percentage change and asks for the original amount. Divide by the multiplier — never subtract or add the percentage directly.

Worked Example 3
A coat's sale price is £68 after a 15% reduction. Find the original price.
1
A 15% reduction gives a multiplier of 0.85 (100% − 15%)
2
The sale price is 0.85 × original, so: original = 68 ÷ 0.85
3
68 ÷ 0.85 = £80
Answer£80

Common trap: you cannot find £80 by adding 15% of £68 to £68 — that gives the wrong answer, because 15% of the original price is not the same as 15% of the reduced price.

Compound interest and repeated percentage change

Compound interest applies the percentage change repeatedly, each time to the new amount — not the original. Use the multiplier raised to the power of the number of time periods.

Worked Example 4
£2000 is invested at 3% compound interest per year. Find the value after 4 years.
1
The multiplier for 3% growth is 1.03
2
Apply it 4 times: 2000 × 1.03⁴
3
2000 × 1.03⁴ = 2000 × 1.12550881 = £2251.02 (to the nearest penny)
Answer£2251.02

Practice questions

Work through each question before checking the answers.

Foundation (Grade 3–5)

Q1Find 20% of £350.Foundation
Q2Increase £60 by 25%.Foundation
Q3Decrease £90 by 10%.Foundation
Q4Write 45 out of 60 as a percentage.Foundation
Q5Find 30% of 90.Foundation

Higher (Grade 5–7)

Q6Increase £240 by 8%.Higher
Q7Decrease £320 by 15%.Higher
Q8A jacket costs £51 in a sale after a 15% reduction. Find the original price.Higher
Q9£1500 is invested at 4% compound interest per year. Find the value after 3 years, to the nearest penny.Higher
Q10Write 84 out of 240 as a percentage.Higher

Higher — Hard (Grade 8–9)

Q11A price including 20% VAT is £96. Find the price before VAT was added.Grade 8–9
Q12A car worth £18,000 depreciates by 12% per year. Find its value after 5 years, to the nearest penny.Grade 8–9
Q13Find 20% of 30% of £500, without finding either percentage of £500 directly first.Grade 8–9
Q14A value is increased by x% then decreased by the same x%, giving an overall decrease of 4%. Find x.Grade 8–9
Q15A savings account pays 5% compound interest per year. After 2 years it is worth £4410. Find the original amount invested.Grade 8–9

Answers

Foundation (Q1–Q5)

Q1£70
Q2£75
Q3£81
Q475%
Q527

Higher (Q6–Q10)

Q6£259.20
Q7£272
Q8£60(51 ÷ 0.85)
Q9£1687.30(1500 × 1.04³ = 1687.296)
Q1035%

Higher — Hard (Q11–Q15)

Q11£80(96 ÷ 1.2)
Q12£9499.17(18000 × 0.88⁵)
Q13£30(0.2 × 0.3 × 500 = 0.06 × 500)
Q14x = 20(1 − (x/100)² = 0.96, so (x/100)² = 0.04, x/100 = 0.2)
Q15£4000(4410 ÷ 1.05²)

Common mistakes

Common Mistake 1
Solving reverse percentage questions by adding or subtracting instead of dividing
If £68 is the price after a 15% reduction, you cannot add 15% of £68 back on — the 15% was taken off a different (larger) starting amount. Always divide by the multiplier instead.
Common Mistake 2
Treating compound interest like simple interest
Compound interest is calculated on the new total each year, not the original amount every time. Using "original × rate × years" instead of "original × multiplier^years" gives the wrong answer for any period beyond the first year.
Common Mistake 3
Using the wrong multiplier for a decrease
A 15% decrease uses the multiplier 0.85 (100% − 15%), not 0.15. Confusing "the percentage removed" with "the multiplier to apply" is one of the most common errors in this topic.
Common Mistake 4
Rounding money too early
Keep full decimal accuracy through every step of a multi-year compound interest calculation, and round to the nearest penny only at the very end.

Exam tips

💡 Exam Tip 1
Always find the multiplier first
Before doing any calculation, write down the multiplier: 100% ± the percentage change, converted to a decimal. This turns almost any percentage question into a single multiplication.
💡 Exam Tip 2
Spot reverse percentage language
Phrases like "after a reduction", "including VAT", or "after depreciation" signal that you're given the final amount and need to divide to find the original — never the other way round.
💡 Exam Tip 3
Use powers for repeated percentage change
Any "per year for n years" question uses multiplier^n. Write this out explicitly (e.g. 1.03⁴) before calculating, so you don't lose track of how many times the multiplier should be applied.
💡 Exam Tip 4
Estimate to sanity-check your answer
Before finalising an answer, check it's a sensible size — an "increase" should always be bigger than the original, and a "decrease" should always be smaller.

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